Question

If `f(x) = 4x^2 + x + 1`, what is `f(b+2)`?

Answer 1

`=4b^2+17b+19`

Explanation:

Just replace all the x's with (b+2) so we have:

`f(b+2)=4(b+2)^2+(b+2)+1`

`=4b^2+16b+16+b+2+1`

`=4b^2+17b+19`