Question

How do you solve `Sin(pi/2 - x) cot(pi/2 + x) = -sin x` from 0 to 2pi?

Answer 1

undefined equation.

Explanation:

sin (pi/2 - x) = cos x (supplementary arc)
`cot (pi/2 + x) = (cos (pi/2 + x))/(sin (pi/2 + x)) = sin x/(-cos x).`
The left side of the equation simplifies to:
`(cos x)(sin x/(-cos x)) = - sin x`,
Then, the equation reduces to:
-sin x = - sin x
The equation is undefined. It is insolvable.