How do you find the intercepts of 4x-3y=12?

1 Answer
Mar 17, 2016

x intercept: (3,0)
y intercept (0;-4)

Explanation:

You have to evaluate the equation for x=0 and y=0

  1. x_nn = x intercept:
    {(4x-3y=12),(y=0):}=>4x=12=>x=12/4=3=>P_(x_nn)(3;0)

  2. y_nn=y intercept
    {(4x-3y=12),(x=0):}=>-3y=12=>y=-12/3=-4=>P_(y_nn)(0;-4)

graph{4x-3y-12=0 [-10, 10, -5, 5]}