How do you find the intercepts of 4x-3y=12?
1 Answer
Mar 17, 2016
Explanation:
You have to evaluate the equation for
-
x_nn = x intercept:
{(4x-3y=12),(y=0):}=>4x=12=>x=12/4=3=>P_(x_nn)(3;0) -
y_nn=y intercept
{(4x-3y=12),(x=0):}=>-3y=12=>y=-12/3=-4=>P_(y_nn)(0;-4)
graph{4x-3y-12=0 [-10, 10, -5, 5]}