Question

How do you simplify `2^(log_2(12))`?

Answer 1

`2^(log_2(12)) = 12`

Explanation:

By definition, the base-`a` log of a number `x` is the value `y` such that `a^y=x`. That is to say

`log_a(x) = y <=> a^y = x`

Then, applying the definition, for any `a`, we have `a^(log_a(x)) = x`

In this case, that gives us `2^(log_2(12)) = 12`