How do you simplify $2^(log_2(12))$ ?

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Answer 1 · 2016-03-17T18:07:18

$2^(log_2(12)) = 12$

By definition, the base- $a$ log of a number $x$ is the value $y$ such that $a^y=x$ . That is to say

$log_a(x) = y <=> a^y = x$

Then, applying the definition, for any $a$ , we have $a^(log_a(x)) = x$

In this case, that gives us $2^(log_2(12)) = 12$

How do you simplify 2^(log_2(12)) 2^(log_2(12)) ?