Question

What is the integral of `int [x * cos(x^2)](dx)`?

Answer 1

`=1/2sin(x^2)+C`

Explanation:

Let
`z=x^2`
then
`=>dz=2xdx`
substituting `xdx=(dz)/2 and x^2=z`
we have
`I=1/2intcos(z)dz=1/2sinz +C=1/2sin(x^2)+C`