How do you find the midpoint of (-3,5) and (4,-2)?

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Answer 1 · 2016-03-19T22:44:47

#(1/2,3/2)#

Call the midpoint #(x,y)#

#x=(-3+4)/2=1/2#

#y=(5+(-2))/2=3/2#

Therefore midpoint is #(1/2,3/2)#

Answer 2 · 2016-03-19T22:53:45

Just another way of writing the same thing:
#P_("mid")->(x,y)=(1/2,3/2)#

Mid point is #1/2# way between given points

Using mean values

Let #P_1 ->(x_1,y_1)->(-3,5)#
Let #P_2->(x_2,y_2)->(4,-2)#

So #" "x_("mid") -> (x_1+x_2)/2 = (-3+4)/2 = +1/2#

So #" "y_("mid") -> (y_1+y_2)/2 = (5-2)/2 = +3/2#

#P_("mid")->(x,y)=(1/2,3/2)#