Question

How do you solve `log(4x-1)=5`?

Answer 1

You first get `log`s on both sides.

Explanation:

Remember that `log10^5=5log10=5xx1=5`
So:
`log(4x-1)=log10^5`

We can now remove the `log`s:
`->4x-1=10^5=100000`

Add `1` to both sides:
`->4x=100001`

`->x=100001/4=25000 1/4or25000.25`