A line passes through #(8 ,2 )# and #(2 ,1 )#. A second line passes through #(3 ,5 )#. What is one other point that the second line may pass through if it is parallel to the first line?
1 Answer
Mar 20, 2016
(9,6)
Explanation:
The first step is to calculate the gradient of the line passing through the 2 given points, using the
#color(blue)" gradient formula "#
# m = (y_2 - y_1)/(x_2 - x_1) # where
#(x_1,y_1)" and " (x_2,y_2)" are 2 coordinate points " # let
# (x_1,y_1)=(8,2)" and " (x_2,y_2)=(2,1) # hence
# m = (1-2)/(2-8) =(-1)/(-6) = 1/6 # The second line is parallel and will also have
# m = 1/6 # There will be an infinite number of points along with (3,5) which will have the same gradient. To find a point (add 1 to y-coord and 6 to x-coord) From definition of gradient.
# rArr (3+6, 5+1) = (9,6) → (15,7)" is another point " #