How do you simplify #i^28#?
1 Answer
Mar 20, 2016
Explanation:
We will use the following:
#i^4 = i*i*i*i = i^2*i^2 = -1*-1 = 1# #a^(bc) = (a^b)^c#
With these, we have
We will use the following:
With these, we have