How do you evaluate log_[16]1 ?

2 Answers
Mar 22, 2016

log_16 1=0

Explanation:

log_16 1
=log 1/log 16-> use change of base property log_bx=logx/logb
=0/log 16->log 1=0
=0

Mar 22, 2016

0

Explanation:

By definition log 1 to any base is equal to 0.

Proof:
Let log_16 1=n
By definition of logarithmic function

16^n=1, This is true only if n=0