How do you evaluate $log_[16]1$ ?

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Answer 1 · 2016-03-22T16:45:22

$log_16 1=0$

$log_16 1$
$=log 1/log 16$ -> use change of base property $log_bx=logx/logb$
$=0/log 16$ -> $log 1=0$
$=0$

Answer 2 · 2016-03-22T17:22:27

0

By definition $log 1$ to any base is equal to $0$ .

Proof:
Let $log_16 1=n$
By definition of logarithmic function

$16^n=1$ , This is true only if $n=0$

How do you evaluate log_[16]1 log_[16]1 ?