How do you evaluate log_[16]1 log161?

2 Answers
Mar 22, 2016

log_16 1=0log161=0

Explanation:

log_16 1log161
=log 1/log 16=log1log16-> use change of base property log_bx=logx/logblogbx=logxlogb
=0/log 16=0log16->log 1=0log1=0
=0=0

Mar 22, 2016

0

Explanation:

By definition log 1log1 to any base is equal to 00.

Proof:
Let log_16 1=nlog161=n
By definition of logarithmic function

16^n=116n=1, This is true only if n=0n=0