How do you condense $log (x + 5) - log x$ $log(x + 5) - log x$ ?

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How do you condense $log (x + 5) - log x$ $log(x + 5) - log x$ ?

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Answer 1 · 2016-03-22T19:47:34

$log (x + 5) - log x$ $log (x+5)-logx$ $= log (\frac{x + 5}{x})$ $=log( (x+5)/x)$

Explanation:

$log (x + 5) - log x$ $log (x+5)-logx$
$= log (\frac{x + 5}{x})$ $=log( (x+5)/x)$ -> use property ${log}_{b} x - {log}_{b} y = {log}_{b} (\frac{x}{y})$ $log_bx-log_by=log_b(x/y)$

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How do you condense $log (x + 5) - log x$ $log(x + 5) - log x$ ?

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