How do you solve #ln(-4x-3) = ln12#?

1 Answer
A08
Mar 25, 2016

#x=-3 3/4#

Explanation:

Solve #ln (-4x-3)=ln12#

We observe that on both sides we have #ln# of the numbers.
Therefore take #"Anti" ln# of both sides
#cancel("Anti" ln)"of"cancel (ln) (-4x-3)=cancel("Anti" ln) "of" cancel(ln)12#
#=>(-4x-3)=12#
or #-4x=12+3#, solving for #x#
#x=-15/4=-3 3/4#

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