How do you find all the zeros of #f(x) = 3(x+5)(x+2)^2 #? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Shwetank Mauria Mar 25, 2016 Zeros of #f(x)# are #-5# and #-2#. Explanation: If #a# is a zero for a function #f(x)#, then #f(a)=0#. As the given #f(x)=3(x+5)(x+2)^2=0# for #x+5=0# and #x+2=0#, the zeros of #f(x)# are #-5# and #-2#. Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 1787 views around the world You can reuse this answer Creative Commons License