Question

How do you rationalize the denominator and simplify `sqrt22/sqrt33`?

Answer 1

`sqrt22/sqrt33=sqrt6/3`

Explanation:

From the given `sqrt22/sqrt33=sqrt22/sqrt33*sqrt33/sqrt33`
`=sqrt(22*33)/(sqrt33)^2=sqrt(2*11*3*11)/33=sqrt(6*11^2)/33=(11sqrt6)/33=sqrt6/3`

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