What is the standard form of # y= (x+7)(x+1)-(3x-7)^2#?

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Answer 1 · 2016-03-28T06:30:10

#y=-8x^2+50x-42#

From the given equation
#y=(x+7)(x+1)-(3x-7)^2#

We start by expanding the right side using multiplication

#y=x^2+8x+7-(9x^2-42x+49)#

#y=x^2+8x+7-9x^2+42x-49#

Simplify

#y=-8x^2+50x-42#

graph{y=(x+7)(x+1)-(3x-7)^2[-80,80,-40,40]}

God bless....I hope the explanation is useful.