Question

How do you graph `x= - (y-2)^2 + 3`?

Answer 1

Vertex `(3, 2)` and it opens to the LEFT
with intercepts at `(-1, 0), (0, 2+sqrt3),(0, 2-sqrt3)`

Explanation:

The graph is a parabola which opens to the left
`x=-(y-2)^2+3`. When we transform the equation to its vertex form
`+-4p(x-h)=(y-k)^2`, it is noticable that there is a negative sign

`-(x-3)=(y-2)^2` that is why this parabola opens to the left.
graph{x=-(y-2)^2+3[-20,20,-10,10]}

God bless...I hope the explanation is useful.