How do you condense $7lnx-2lny$ ?

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Answer 1 · 2016-03-28T08:35:59

$ln(x^7/y^2)$

We may use the identities $lna-lnb=ln(a/b)$ and $alnb=lna^b$ .

Using them $7lnx-2lny$

= $lnx^7-lny^2$

= $ln(x^7/y^2)$

How do you condense 7lnx-2lny 7lnx-2lny ?