Question

How do you find another point on each line using slope and point given m=-3/4; passes through (0,0)?

Answer 1

Point 1`-> (x,y)-> (-3, 2 1/4)`

Point 2`->(x,y)->(+3,-2 1/4)`

Explanation:

Standard form for a straight line is `y=mx+c`

We are constrained by two parameters (conditions)

If both lines pass through the point `P->(x,y)->(0,0)`

The slope `m=-3/4`.

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The given conditions within context of the question implies that there is only one line and that it passes through the given point.

So given condition `P->(x,y)->(0,0)`

`=> y=mx+c" "->" "0=m(0)+c`

This means that `c=0` so our equation becomes:

`y=mx`

We are told that `m=-3/4`

So we now have:

`y= -3/4x` as our equation.

All we have to do now is substitute value for `x` and calculate the related value for `y`