How do you factor #9c^2 - 25d^4#? Algebra Polynomials and Factoring Factoring Completely 1 Answer ali ergin Mar 30, 2016 #9c^2-25d^4=(3c-5d^2)*(3c+5d^2)# Explanation: #9c^2-25d^4=(3c)^2-(5d^2)^2# #3c=a# #5d^2=b# #(3c)^2-(5d^2)^2=a^2-b^2# #a^2-b^2=(a-b)*(a+b)# #9c^2-25d^4=(3c-5d^2)*(3c+5d^2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1271 views around the world You can reuse this answer Creative Commons License