How do you write the equation in slope intercept form given (-2, -1), (4, -4)?

1 Answer

#y=-1/2x-2#
with slope #m=-1/2# and y-intercept #b=-2#

Explanation:

We start with the Two Point Form

#y-y_1=((y_2-y_1)/(x_2-x_1))(x-x_1)#

with #P_2(x_2, y_2)=(4, -4)#
and #P_1(x_1, y_1)=(-2, -1)#

Compute slope #m=(y_2-y_1)/(x_2-x_1)=(-4--1)/(4--2)=-3/6=-1/2#

#y-y_1=((y_2-y_1)/(x_2-x_1))(x-x_1)#

#y--1=-1/2(x--2)#

#y=-1/2x-1-1#

#y=-1/2x-2" "#the required equation

Kindly see the graph of #y=-1/2x-2# passing thru with #P_2(4, -4)# and #P_1(-2, -1)#

desmos

God bless....I hope the explanation is useful