How do you find all zeros of the function #f(x) = x^2 - 12x + 20#?

1 Answer
Apr 2, 2016

zeros of #f(x)# are #x=2# and #x=10#

Explanation:

#f(x)=x^2-12x+20#

We look for two numbers which when multiplied together equal #20#
and which when added together equal #(-12)#

With a bit of though we come up with #(-2)# and #(-10)#
which allows us to factor:
#f(x)=x^2-12x+20=(x-2)(x-10)#

For #f(x)# to be zero
either
#color(white)("XXX")(x-2)=0 rarr x=2#
or
#color(white)("XXX")(x-10)=0 rarr x=10#