Question

What's the area of the first quadrant region bounded by the y-axis, the line `y=4-x` and the graph of `y=x-cosx`?

Answer 1

Area`=4.93888" "`square units

Explanation:

Area`=int_0^(1.85825)[(4-x)-(x-cos x)]dx`

Area`=int_0^(1.85825)(4-2x+cos x)dx`

Area `=(4x-x^2+sin x)` Evaluate this integral from `0` to `1.85825`

Make sure your calculator is set to the RADIAN mode

Area `=4(1.85825)-(1.85825)^2+sin(1.85825)-(4(0)-0^2+sin 0)`

Area `=4.93888" "`square units

graph{(y-4+x)(y-x+cos x)=0[-10,10,-5,5]}

God bless....I hope the explanation is useful.