How do you evaluate #cot((2pi)/3)#?

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Answer 1 · 2016-04-04T19:59:35

#1.402#

Evaluate #(2pi)/3# where #pi = 180^o#, which gives a value of #120^o#.

Also know that #cot = 1/tan#.

Therefore,

#cot((2pi)/3) = 1/(tan(120)) = 1/0.713 = 1.402#

Answer 2 · 2016-04-05T00:00:18

# - sqrt3/3#

Trig table --> #tan ((2pi)/3) = - sqrt3#
Therefor,
#cot ((2pi)/3) = 1/(tan) = - 1/sqrt3 = - sqrt3/3#