Question

500.0 mL of a gas is collected at 745.0 mm Hg. What will the volume be at standard pressure?

Answer 1

This is an application of Boyle's Law.

Explanation:

`P_1V_1 = P_2V_2`. This form is useful in that we do not have to convert volume and pressure to standard forms. We can even use the non-standard pressure measurement of `mm` `Hg`.

`1` `atm` `=` `760` `mm` `Hg`. So the volume of your gas should slightly reduce:

`V_2 = (P_1xxV_1)/(P_2)` `=` `(745*mm*Hgxx500.0*mL)/(760*mm*Hg)` `=` `??` `mL`.

Note that here (reasonably) a constant temperature is assumed.