How do you factor the expression $32 v^{2} - 2$ $32v^2-2$ ?

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How do you factor the expression $32 v^{2} - 2$ $32v^2-2$ ?

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Answer 1 · 2016-04-07T03:36:29

2(4v-1)(4v+1)

Explanation:

Take 2 out as a common factor: $2 (16 v^{2} - 1)$ $2(16v^2-1)$
The factored answer is a "difference of squares": $(n^{2} - m^{2}),$ $(n^2-m^2),$ where n and m are perfect squares.
Therefore, when factored as a "difference of squares":
$2 (4 v - 1) (4 v + 1)$ $2(4v-1)(4v+1)$

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How do you factor the expression $32 v^{2} - 2$ $32v^2-2$ ?

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