How do you solve #log (9x + 7) = 3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer A. S. Adikesavan Apr 8, 2016 #x = 331/3#. Explanation: #log(8x+7)=3.# #10^(log_(10)(9x+7))=10^3# #10^(log_10(a))=a# So, 9x+7 = 1000. x = 993/9=331/3#.., Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1143 views around the world You can reuse this answer Creative Commons License