How do you solve 5x^3 - 320 x = 0? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer ali ergin Apr 8, 2016 x=±8 Explanation: 5x^3-320x=0 cancel(5)cancel(x)^3=cancel(320)cancel(x) x^2=64 sqrt (x^2)=sqrt64 sqrt(x^2)=sqrt 8^2 x=±8 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1903 views around the world You can reuse this answer Creative Commons License