Question

What is the equation of the line perpendicular to `y=-9/16x` that passes through `(-12,5)`?

Answer 1

`y=16/9x+79/3`

Explanation:

The given line is

`y=(-9)/16x`

Two Lines are perpendicular if `m_1 xx m_2=-1`
Where -

`m_1:` slope of the given line
`m_2:` slope of the required line

Then `m_2=-1 xx 1/m_1`

`m_2=-1 xx 16/(-9)=16/9`

The equation of the required line is -

`y-y_1=m_2(x-x_1)`
`y-5=16/9(x-(-12))`
`y=16/9x+12(16/9)+5`
`y=16/9x+79/3`