Question

How do you factor the trinomial `v^3 - 4v^2 - 45v`?

Answer 1

`v(v-9)(v+5)`

Explanation:

Taking `v` out as a common factor, we get:

`v(v^2-4v-45)`

Now what we have is a quadratic multiplied by a common factor.
Factorising the quadratic we get the fully factored function:

`v(v-9)(v+5)`