Question

How do you simplify `(b^3 a^5)/(b^2 a^4)`?

Answer 1

`(b^3a^5)/(b^2a^4)=ba`

Explanation:

`(b^3a^5)/(b^2a^4)=(b*b*b*a*a*a*a*a)/(b*b*a*a*a*a)`

So you should cancel b's and a's in nominator and denominator. So the result would be `b*a`.

More scientifically:

`(b^3a^5)/(b^2a^4)= b^(3-2) * a^(5-4) = b^1 * a^1 = b*a`

Answer 2

ab

Explanation:

Using the following `color(blue)" rule of exponents "`

`color(red)(|bar(ul(color(white)(a/a)color(black)( a^m/a^n hArr a^(m-n))color(white)(a/a)|)))`

`rArr (b^3a^5)/(b^2a^4) = b^3/b^2xxa^5/a^4 = b^(3-2)xxa^(5-4) = ab`