How do you solve #3/4x - 6 = 1/2x - 9 #?

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Answer 1 · 2016-04-11T05:38:57

#x = -12 #

#color(blue)(3/4 x) - 6 = color(blue)( 1/2x)-9 #

#color(blue)(3/4 x - 1/2x) = -9 + 6 #

#3/4 x - ((1 *2 )/ (2 *2))x = -3 #

#3/4 x - (2 )/ (4)x = -3 #

#1/ 4x = -3 #

#x = -3 * 4 #

#x = -12 #

Answer 2 · 2016-04-11T09:05:39

#x=-12#

#color(blue)(3/4x-6=1/2x-9#

#rarr(3*x)/4-6=(x*1)/2-9#

#rarr(3x)/4-6=x/2-9#

Add #6# both sides

#rarr(3x)/4cancel(-6color(perple)(+6))=x/2-9color(purple)(+6)#

#rarr(3x)/4=x/2-3#

Subtract #x/2# both sides

#rarr(3x)/(4)-color(purple)(x/2)=cancel(x/2)-3-cancel(color(purple)(x/2#

By subtracting the fractions

#rarr(3x-2x)/4=-3#

#rarrx/4=-3#

Multiply both sides by #4#

#rarrx/cancel(4)*cancelcolor(purple)(4)=-3*color(purple)(4)#

#color(green)(rArrx=-12#