Question

How do you convert `3x+2y=16` to polar form?

Answer 1

In polar form : `3 cos theta+4sin theta=16/r`

Explanation:

In polar form we know `r^2=x^2+y^2 ; x=rcostheta ;y =rsin theta and theta=tan^-1(y/x)` So `3*r*cos theta+4*r*sin theta=16 or 3 cos theta+4sin theta=16/r`[Ans]