For the Cartesian coordinate axes, we have the following depiction:
For quadrant #"I"#, the coordinates are both positive, i.e. you have #(x,y)# where #x,y > 0#. So, it is in the upper-right.
For quadrant #"II"#, you have #(x,y)# where #y > 0# but #x < 0#. So, it is in the upper-left.
For quadrant #"III"#, the coordinates are both negative, i.e. you have #(x,y)# where #x,y < 0#. So, it is in the lower-left.
For quadrant #"IV"#, you have #(x,y)# where #x > 0# but #y < 0#. So, it is in the lower-right.
Using that information, I'll bounce the question back to you: what quadrant is #(2,4)# in? For this, #x = 2# and #y = 4#; that is, #x# is two units to the right of #0#, and #y# is four units above #0#.
