Question #f05fa

1 Answer
Alan P.
Apr 12, 2016

#lim_(hrarr0)(h^2+h)/h=1#

Explanation:

Assuming that I have reformatted your question into the form you intended:

#lim_(hrarr0) (h^2+h)/h#

#color(white)("XXX")=lim_(hrarr0) (cancel(h)(h+1))/cancel(h)#

#color(white)("XXX")=lim_(hrarr0)h+1#

#color(white)("XXX")=1#

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