How do you graph #g(x)= log_6 x#?

1 Answer
Apr 13, 2016

Using that #log_6(x)# is defined to be the value such that #6^(log_6(x)) = x#, we can find points to plot by using that

#g(6^k)=log_6(6^k) = k# for any choice of #k#. For example, we would have points such as #(1,0), (6, 1), (36, 2)# as well as #(1/6, -1), (1/36, -2)#.

In general, logarithmic functions tend to #-oo# as #x# approaches #0#, so we have a vertical asymptote at #x=0#. After that, you can use some easily plotted points such as the ones above to see approximately how the curve grows. In this case, the graph will be as follows:

graph{log(x)/log(6) [-2, 9, -3.5, 2]}