What is the value of #f(x) = -x^2 + 8x - 6# when #f(2)#?

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Answer 1 · 2016-04-14T02:45:11

#f(2)=6#

Given equation #f(x)=-x^2+8x-6# and we need to find #f(2)#

#f(2)# means that #x=2#

So, we need to substitute #x=2# into #f(x)=-x^2+8x-6# to get #f(2)#;

#f(x)=-x^2+8x-6#

#f(2)=-(2)^2+8(2)-6#

#f(2)=-4+16-6#

#f(2)=6#