A solution was prepared by dissolving 66.6 g of calcium chloride in enough water to make 175 mL of solution. This solution was then further diluted to a total of 550 mL with water. What was the concentration of the final solution?

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Answer 1 · 2016-04-16T12:59:47

#"Concentration "="Moles of solute"/"Volume of solution"#, #"approx. "1*mol*L^-1#

#C# #=# #n/V#, where #n=(66.6*g)/(110.98*g*mol^-1)# #=# #0.600# #mol#.

The final volume of the solution is #550xx10^-3*L#

So #"Concentration with respect to "CaCl_2=(0.600*mol)/(550xx10^-3*L)# #=# #??#

What is the concentration with respect to #Ca^(2+)(aq)#, to #Cl^(-)(aq)#?