A chemist performs the synthesis of sodium chloride from its elements. The chemist begins with 46 grams of sodium. How many moles of chlorine are needed? 2 Na + Cl2 → 2 NaCl

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A chemist performs the synthesis of sodium chloride from its elements. The chemist begins with 46 grams of sodium. How many moles of chlorine are needed? 2 Na + Cl2 → 2 NaCl

I didn't understand that is it asking about Cl (chlorine) or Cl2 (Chlorine GAS)...

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Answer 1 · 2016-04-16T15:25:21

We have $2$ $2$ $m o l$ $mol$ of sodium metal to start; clearly we need the 1 mole of $C l_{2} (g)$ $Cl_2(g)$ .

Explanation:

$Moles of sodium = \frac{46.0 \cdot g}{22.9 \cdot g \cdot m o l^{- 1}} = 2 \cdot m o l$ $"Moles of sodium "=(46.0*g)/(22.9*g*mol^-1)=2*mol$ .

Given your equation, clearly we need the ONE mole of $C l_{2}$ $Cl_2$ gas. What is the mass of this quantity of chlorine?

It is fact that all of the elemental gases EXCEPT for the Noble Gases are diatomic: $N_{2}, O_{2}, F_{2}, C l_{2}$ $N_2, O_2, F_2, Cl_2$ . Of course, all the halogens, as the elements, are diatomic, but not all are gaseous.

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A chemist performs the synthesis of sodium chloride from its elements. The chemist begins with 46 grams of sodium. How many moles of chlorine are needed? 2 Na + Cl2 → 2 NaCl

I didn't understand that is it asking about Cl (chlorine) or Cl2 (Chlorine GAS)...

1 Answer

Explanation:

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