What is (16x^3)/(5y^9) * (x^3y^7)/(80xy^2)?

1 Answer
Apr 17, 2016

=(x^5)/(25y^4)

Explanation:

(16x^3)/(5y^9)*(x^3y^7)/(80xy^2)

You can cross cancel 16 and 80 because both are multiples of 16. So 16 div 16 = 1 and 80 div 16 = 5.
(x^3)/(5y^9) times (x^3y^7)/(5xy^2)

Cancel out terms. You will need to know this: (a^m)/(a^n)=a^(m-n)

=(x^5)/(25y^4)