Question #4badc

1 Answer
Apr 19, 2016

0.8 mol

Explanation:

As per the equation

#H_2# (g) + #O_2# (g) -----> 2#H_2#O (l)

1 mol of #O_2# is required to produce 2 moles of #H_2#O

x mol of #O_2# is required to produce 1.60 moles of #H_2#O

setting up the ratio , we get

(1 mol of #O_2 # / X mol of # O_2#) = (2 mol of #H_2#O / 1.6 mol of #H_2#O)

1 / x = 2 /1.6

1 x 1.6 = 2.x

1.6 = 2x

x= 0.8 mol