How do you find all the zeros of #x^2 + 24 = 11x#?

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Answer 1 · 2016-04-19T14:01:22

#=>x^2-11x+24=0#
#=>x^2-8x-3x+24=0#
#=>x(x-8)-3(x-8)=0#
#=>(x-8)(x-3)=0#
#: . x= 3and x= 8# are the two values for zero