How do you solve #8^(5x) = 4.4#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Bdub Apr 21, 2016 #x=ln4.4/(5ln8) ~~0.143# Explanation: #ln8^(5x)=ln4.4# #(5x)ln8=ln4.4# #5x=ln4.4/ln8# #x=ln4.4/(5ln8) ~~0.143# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1368 views around the world You can reuse this answer Creative Commons License