Question

How do you evaluate `log_(6)x + log_(6)3 = 2`?

Answer 1

`x=12`

Explanation:

Use Property:`log _b(xy)=log_bx+log_by and y=log_bx iff b^y=x`

`log_6(3x)=2`

`6^2 = 3x`

`36/3=x`

`x=12`