Question

How do you solve for x in `1.76 = 2.718 ^ (.0093*x)`?

Answer 1

`x=ln1.76/(0.0093ln2.718) ~~60.79`

Explanation:

`ln 1.76=ln 2.718^(0.0093x)`

`ln1.76=(0.0093x) ln2.718`

`ln1.76/ln2.718=0.0093x`

`x=ln1.76/(0.0093ln2.718) ~~60.79`