How do you simplify #6(2p+1)#?

Question

1802 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-22T11:57:56

#=6xx2p+6xx1=12p+6#

Answer 2 · 2016-04-22T12:03:45

#12p+6#

Given:#" "6(2p+1)#

#color(blue)("Using first principles")#

This is the same as #6xx(2p+1)#

So you have 6 lots of #(2p+1)#

Which means you have:

6 lots of #2p# and 6 lots of #(+1)# which gives

#2p+2p+2p+2p+2p+2p + 6#

This is the same as: #12p+6#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Shortcut method")#

Multiply everything inside the brackets by 6 giving

#12p+6#