How do you find the slope given A(-3,2) and B ( 0,4)?

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How do you find the slope given A(-3,2) and B ( 0,4)?

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Answer 1 · 2016-04-22T12:05:06

$m = \frac{2}{3}$ $m=2/3$

Explanation:

$A (- 3, 2)$ $A(-3,2)$
$B = (0, 4)$ $B=(0,4)$
$A_{x} = - 3$ $A_x=-3$
$A_{y} = 2$ $A_y=2$
$B_{x} = 0$ $B_x=0$
$B_{y} = 4$ $B_y=4$
$m = slope$ $m="slope"$

$m = \frac{B_{y} - A_{y}}{B_{x} - A_{x}}$ $m=(B_y-A_y)/(B_x-A_x)$

$m = \frac{4 - 2}{0 + 3}$ $m=(4-2)/(0+3)$

$m = \frac{2}{3}$ $m=2/3$

Answer 2 · 2016-04-22T12:06:53

$m = \frac{2}{3}$ $m=2/3$

Explanation:

To solve this, we can use the gradient formula: $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$ , where $x_{1}, y_{1}$ $x_1,y_1$ are the coordinates of the first point, $x_{2}, y_{2}$ $x_2,y_2$ are the coordinates of the second point, and $m$ $m$ is what the slope.

Let's call $(- 3, 2)$ $(-3,2)$ the first point and $(0, 4)$ $(0,4)$ is the second point, although it doesn't matter which one is the first or second, you'll always get the same answer. Applying this:

$m = \frac{4 - 2}{0 - (- 3)}$ $m=(4-2)/(0-(-3))$
$m = \frac{2}{3}$ $m=2/3$

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How do you find the slope given A(-3,2) and B ( 0,4)?

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