Question

What is the vertex of the parabola `y = (x-4)^2`?

Answer 1

`(4,0)`

Explanation:

Standard form;`" "y=ax^2+bx+c`
Vertex form;`" "y=a( x+ b/(2a))^2+k`

So your given equation is in vertex form in that we have:

`" "y=1(x-4)^2+0`

Where `x_("vertex")=(-1)xxb/(2a) -> (-1)xx(-4) = +4`

`" "y_("vertex")=k ->0`

`color(blue)("Vertex "->(x,y)->(4,0)`