Question

How do you factor completely `2x^2 + 36x + 162`?

Answer 1

See below..

Explanation:

`2x^2 + 36x + 162` (divide 2) gives you:
`x^2 + 18x + 81`, then you have to factorise it.

When you factorise it, it should look like that: `(x + a)(x + b) = 0`

But before you factorise, you should first find out what factors (a and b) of 81 that add to 18. In that case, 9 and 9 are the factors that add to 18 and multiply to 81.

`(x+9)(x+9)`