How do you evaluate #sin^2 ((pi)/6)#?
2 Answers
Apr 27, 2016
Explanation:
So
Apr 27, 2016
Explanation:
# sin^2(pi/6) = sin(pi/6)xxsin(pi/6)# and using the
# color(blue)" Exact value triangle ""for this angle"#
# sin(pi/6) = 1/2 #
#rArr sin^2(pi/6) = 1/2xx1/2 = 1/4 #